Steelers RB DeAngelo Williams Named AFC Offensive Player of the Week

DeAngelo Williams

Monday night in the Nation’s Capital Steelers running back DeAngelo Williams didn’t allow the team to miss a beat without usual starting running back Le’Veon Bell, and for his efforts today he was named the AFC Offensive Player of the Week for Week One.

All DA did against the Redskins was dominate to the tune of 143 yards on the ground with two scores, and he also pulled in six passes for 28 yards in the 38-16 win.

Both of Williams’ TD’s came in the fourth and final quarter as the Steelers put the game away to get to 1-0 on the season. Williams will get another crack to have a big week for Bell this Sunday as the Steelers host the Bengals.

About the Author

Matt Loede
Matt Loede has been in the sports media for over 16 years, with experience covering the MLB, NBA, and NFL. On Sunday’s during football season, you can hear Matt on national networks like Fox Sports Radio, Associated Press, and others. Born and raised in Cleveland Ohio, Matt studies and talks football inside and out, and is anxious to share his thoughts and comments with readers on a daily basis.

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